The Beaver Games are an annual competition consisting of three rounds. The beavers always play individually, but in the team rounds (round 1 and 2), the individuals' scores are added together to get a team score.海狸运动会是一项年度赛事，由三轮比赛组成。海狸们总是单独参赛，但在团队赛（第一轮和第二轮）中，个人得分会累加起来得出团队总分。
The teams in round 1 consist of four beavers and are selected by lottery. The team with the highest sum of points wins and advances to the next round. In round 2, new teams of two are selected, again by lottery, from the four beavers who advanced from round 1. The final round is a head-to-head between the two beavers from the winning team from round 2. If you win three rounds in a row, you are the overall winner.第一轮的队伍由四只海狸组成，通过抽签决定。总分最高的队伍获胜并晋级下一轮。第二轮中，从第一轮晋级的四只海狸中再次通过抽签选出两两一组的新队伍。决赛是第二轮获胜队伍中的两只海狸之间的对决。如果你连续赢得三轮，你就是最终的获胜者。
To make sure everyone has fun, even the beavers who do not advance to the next round still do all the activities and their scores are recorded so that next year they can aim for a PB (personal best score).为了确保每个人都能玩得开心，即使那些未能晋级下一轮的海狸也参与所有活动，他们的得分会被记录下来，这样明年他们就可以争取个人最好成绩（PB）。
Beaver Ada 
was the lucky winner of this year's Beaver Games.海狸阿达是今年海狸运动会的幸运冠军。
For each challenge, the individual points are given in the table below.对于每个挑战，其对应的个人得分见下表。
| Beaver: 海狸: | |
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 |
 |
 |
 |
 |
 |
| Round 1 第一轮 | 15 | 16 | 19 | 18 | 17 | 20 | 19 | 19 |
| Round 2 第二轮 | 20 | 27 | 30 | 24 | 28 | 24 | 30 | 30 |
| Round 3 第三轮 | 10 | 14 | 11 | 15 | 16 | 13 | 9 | 12 |
Question 问题:
Which three beavers were in Ada's first team?阿达的第一组里有哪三只海狸？
(Drag and drop them onto the question marks. Press 'Save' when you have finished.)（将它们拖放到问号处。完成后按“保存”。）
Explanation 解释
Answer: 答案:
Ada's team in round 1:艾达在第一轮的团队成员：
Explanation: 解释:
The third challenge is an individual match. Since Beaver G is the only player who has fewer points than Ada, they must have been on the same team in the second challenge.第三个挑战是单人赛。由于海狸 G 是唯一一个得分比艾达少的选手，所以他们在第二个挑战中肯定是在同一队。
Their sum of points in the second challenge is 50. This must be higher than the sum of points of the other two-person-team. The two players D and F are the only other ones whose sum of points is less than 50. Therefore, they have to have been in the same team as Ada and G in the first challenge. Since we now know these members, we actually don't have to check the members of the other team.他们在第二项挑战中的总分是 50 分。这必须高于另一支两人队伍的总分。D 和 F 是仅有的总分低于 50 分的另外两名选手。因此，他们肯定在第一项挑战中与艾达和 G 在同一队。既然我们现在已经知道了这些队员，实际上就不必再去查看另一支队伍的队员了。
So this means that in the first challenge the team of (Ada, D, F and G) has 72 points while (B, C, E and H) had 71 points. So Ada's team wins. In the second challenge, (Ada and G) had 50 points and (D and F) had 48 points. In the third challenge, Ada wins with 10 points against G with 9 points. So Ada is the overall winner.这意味着在第一个挑战中，（阿达、D、F 和 G）队获得了 72 分，而（B、C、E 和 H）队获得了 71 分。所以阿达的队伍获胜。在第二个挑战中，（阿达和 G）获得了 50 分，（D 和 F）获得了 48 分。在第三个挑战中，阿达以 10 分战胜了 G 的 9 分。所以阿达是总胜者。
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